Answer:
a. 255.255.255.0 (class C)
b. 255.255.255.224
Explanation:
Here, we want to give the implied subnet mask of the given classful IPV4 address
We proceed as follows;
Given IPv4 address: 200.200.200.200
Classes
Class A : 0.0.0.0 to 127.255.255.255
Class B: 128.0.0.0 to 191.255.255.255
Class C: 192.0.0.0 to 223.255.255.255
Class D: 224.0.0.0 to 239.255.255.255
so 200.200.200.200 belongs to Class C and it's subnet mask is 255.255.255.0
In CIDR(Classless Inter Domain Routing)
subnet /27 bits means 27 1s and 5 0s. so subnet
i.e 11111111.11111111.11111111.11100000 which in dotted decimal format is 255.255.255.224 .
Answer:
I have got no idea it looks like an older style
Answer:
The answer is "Option c".
Explanation:
In the given question the device A is connected by 3 wires, contributing all of them, which also includes several connector paths. When all the wires of A are broken down, and if all of this leaves no routes that can be used. Even so, if it is done to E, it's also linked to four different routes. Its solution would've been C because its value will be the MINIMUM.
Given, a = 3, r = 1/2, n = 10
%r is common ratio
%n is number of terms
%a is the first term of the series
Sum = 0;
a = 3;
r = 1/2;
for i = 0 : 1 : 10;
Sum = Sum + a * r ^ i;
end
Sum