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geniusboy [140]
4 years ago
14

while performing a sonogram, to minimize risk to the fetus, which imaging mode trade off would be most appiclable.

Physics
1 answer:
Alexus [3.1K]4 years ago
7 0

Answer: Use M-mode instead of pulse-wave Doppler to measure the fetal heart rate.

Explanation: M-mode is a famous ultrasound process during the early days of Ultrasound technologies, M-mode has a very high sampling rate. One of the major disadvantages is that it may be difficult to align the M-mode to be the perpendicular to the SEPTUM. M-mode has only one (1) dimensional view of an object,to minimize the risk to the Fetus, M-mode is the most applicable tradeoff. Specifically, M-mode is mainly used because of its Axial and temporal resolution of the structure of objects.

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The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between t
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For First Drawing

F =\frac{ k q^2}{d^2}+\frac{k q^2}{d^2}  

F =\frac{2* 9*10^9* (1.6*10^-6)^2}{ (2.6*10^-3^2}

F = 6816.5680 N

For second Drawing

F' =\frac{ k q^2}{d^2 }-\frac{ k q^2}{ d^2}  

F' = 0 N

For Third Drawing

F'' =\frac{ k q^2}{d^2} * \sqrt (2)

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F''=28195.5N

4 0
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