Answer:
-5.1 kg m/s
Explanation:
Impulse is the change in momentum.
Change in momentum= final momentum - initial momentum=m +m
Plugging in the values= -0.15*24 - (0.15*10) (The motion towards the pitcher is negative as the initial motion is considered to be positive)
Impulse=-5.1 kg m/s (-ve means that it is the impulse towards the pitcher)
Answer:
R = 1.2295 10⁵ m
Explanation:
After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body
θ = 1.22 λ / D
where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture
how angles are measured in radians
θ = y / R
where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens
R =
let's calculate
R =
R = 1.2295 10⁵ m
Answer:
(a) Total north component = (26.89 + 25) = 51.89 metres
(b) Total west component = (-34.83 + 52) = 17.17 metres.
Explanation:
Do northwest components first.
North component = (sin 33.9 x 44) =26.89 metres.
West component = (cos 33.9 x 44) = -34.83metres.
Total west component = (-34.83 + 52) = 17.17 metres.
Total north component = (26.89 + 25) = 51.89 metres
Answer:
Induced emf,
Explanation:
It is given that,
Rate of change of magnetic field,
A UHF antenna is oriented at an angle of 47° to a magnetic field, θ = 47°
Diameter of the antenna, d = 13.4 cm
Radius, r = 6.7 m = 0.067 m
We need to find the induced emf of the antenna. It is given by :
Where
= magnetic flux,
So,
B = magnetic field
So, the induced emf of the antenna is 2.2 mV. Hence, this is the required solution.
Answer:
Explanation:
For this case we know that the speed of the sound is given by:
And we have the following info provided:
represent the car leading
represent the car behind with the source
is the frequency for the observer
And we can find the frequency of the source with the following formula:
And replacing we got:
So then the frequency for the source would be the same since the both objects are travelling at the same speed.