A diver is on a board 1.80 m above
2 answers:
Answer:
v = 6.95 m/s
Explanation:
Given that,
A diver is on a board 1.80 m above the water, s = 1.8 m
The initial speed of the diver, u = 3.62 m/s
Let v is the speed with which she hit the water. It will move under the action of gravity. Using the equation of motion as follows :
So, she will hit the water with a speed of 6.95 m/s.
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Explanation:
The Coulomb's law states that the force acting on two charges is directly proportional to the product of charges and inversely proportional to the square of distance between them . Mathematically, it is given by
Where
k is the electrostatic constant
q₁ and q₂ are charges
r is the distance between them.
The SI unit of electric force is Newton. It can be attractive or repulsive. The attraction or repulsion depend on charges. If both charges are positive, the force is repulsive and if both are opposite charges, the force is attractive.
Answer:
R = 0.237 m
Explanation:
To realize this problem we must calculate the moment of inertia of the wheel formed by a thin circular ring plus the two bars with an axis that passes through its center.
The moments of inertia of the bodies are additive quantities whereby we can add the mounts inertia of the ring and the two bars.
Moment of inertia ring I1 = MR²
Moment of inertia bar I2 = 1/12 ML²
Moment of inertia disk I3 = ½ mR²
Let's calculate the moment of inertia of the wheel
I = I1 + 2 I2
I = MR² + 2 1/12 ML²
The length of the bar is ring diameter
L = 2R
I = 5.65 0.156² + 1/6 9.95 (2 0.156)²
I = 0.1375 + 0.1614
I = 0.2989 kg m²
This is the same moment of inertia of the solid disk,
Disk
I3 = I
I3 = ½ MR²
They give us disk density
ρ = M / V
M = ρ V
M = ρ (pi R² e)
Done is the thickness of the disc, in general it is e= 1 cm = 0.01 m
Let's replace
I3 = ½ ( ρ π R²) R²
I3 = ½ ρ π e R⁴
R⁴ = 2 I3 / ( ρ π e)
R = ( 2 I3 / ( ρ π e)
R⁴ = 2 0.2989 / (5990 π 0.01)
R = 0.237 m