A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
1 answer:
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well, about A and D, I just plugged the values on the slope formula of
for A the values are 8.01 and 8.0, so indeed those "slopes" are close.
for D the values are -2.25 and 8.0, so no dice on that one.
for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.
checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice.
for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.
for E, do they intercept at (2,1)? well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent.
for F, we know the slope of the line L(x) is 8, is g'(2) = 8? let's check
recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice.
Answer:
0.6,0.7,0.3 neither disjoint nor independent.
Step-by-step explanation:
Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.
A= visa card
B = Master card
P(A) = 0.60 and P(B) = 0.40
P(AUB)' = 0.30
i.e. P(AUB) = 0.70
Or P(A)+P(B)-P(AB) =0.70
P(AB)= 0.30
Randomly select a student from the university.
1) the probability that this student does not have a MasterCard.
2. the probability that this student has either a Visa card or a MasterCard.
=
3. Calculate the probability that this student has neither a Visa card nor a MasterCard.
=
4. Are the events A and B disjoint? Are the events A and B independent?
A and B have common prob 0.30 hence not disjoint.
P(AB) ≠P(A)P(B)
Hence not independent