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Pavlova-9 [17]
4 years ago
6

A golf ball is selected at random from a golf bag. If the golf bag contains 6 green ​balls, ​5 red balls, and 9 brown ​balls, fi

nd the probability of the following event. The golf ball is green or red . The probability that the golf ball is green or red is nothing. ​(Type an integer or a decimal rounded to three decimal places as​ needed.)
Mathematics
1 answer:
Scrat [10]4 years ago
8 0
First you would do 6+5+9 which equil 20 (The amount of golf balls) then you divide by the amount of green and red balls there are. Add up 6+5 which equal 11. Then divide 20/11 which is about 1.818%. If you have any questions feel free to ask!
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The trapezoid's area is 126 inch².

Step-by-step explanation:

Step 1:

The trapezoid's area is calculated by averaging the base lengths and multiplying it with the trapezoid's height.

The trapezoid's area, A = \frac{b_{1}+b_{2}}{2} h.

Here b_{1} is the lower base and b_{2} is the upper base, height is h.

Step 2:

In the given diagram,

b_{1} = 12 inches and b_{2}= 2+12+2=16 inches and h = 9 inches.

A = \frac{b_{1}+b_{2}}{2} h = \frac{12+16}{2} (9) = 14(9)= 126 inch².

So the given trapezoid's area is 126 inch².

8 0
4 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
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