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guapka [62]
3 years ago
12

Can anyone help me with this Midterm Advanced Algebra problem. (DONT ANSWER IF YOUR NOT SURE)

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

2

Step-by-step explanation:

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Help me plz 10 points. its only middle school work. one question.
AnnZ [28]

Answer:

98

Step-by-step explanation:

6 0
2 years ago
If f is a continuous function such that the integral from 1 to 4 of f of x, dx equals 10, evaluate the integral from 2 to 8 of 2
IgorLugansk [536]

Answer: 10

Step-by-step explanation:

Since integral from 1 to 4 of f(x) =10

To evaluate integral from 2 to 8 of 2 times f(2x), using substitution method

Let U = 2x, dU = 2dx, dx = dU/2

Evaluate the limit, upper limit gives dU = 2*4 = 8, lower limit gives dU = 2*1 = 2.

Since this limit are the same as the limit for the question,

Therefore, F(4) - F(1) = F(8) - F(2) = 10

Substituting dx=dU/2

Gives,

Integral from 2 to 8 of 2 times f(2x)= (1/2)(2)(F(8)-F(2)) = 10

6 0
3 years ago
The reacttimes data set has 50 observations of human reaction times to a physical stimulus. The reaction times are named times a
scoundrel [369]

Solution: The formula for mean is:

Mean=\frac{\sum x}{n}

Where:

\sum x is the sum of given observations

n is the number of observations

\sum x=87.12

n=50

\therefore Mean =\frac{87.12}{50}= 1.74 rounded to two decimal places

To find the median, we need to first arrange the data in ascending order but we are already given the data in ascending order.

Therefore, the median is:

Median=\left(\frac{n+1}{2} \right)^{th} item

                  =\left(\frac{51}{2} \right)^{th} item

                  =25.5^{th} item

                  =1.52+0.5(1.54-1.52)

                  =1.52+0.01

                  =1.53

Therefore, the median = 1.53

4 0
3 years ago
A turtle crawled at a speed of 1.2 meters per minute for 9 minutes. How far did the turtle crawl? 7.5 meters 7.8 meters 10.2 met
Dennis_Churaev [7]

Answer:

10.8 meters

Step-by-step explanation:

3 0
3 years ago
It is assumed that the mean weight of a Labrador retriever is 70 pounds. A breeder claims that the average weight of an adult ma
Sindrei [870]

Answer:

z(s) is in the acceptance region we accept H₀. We don´t have enough evidence to support the breeder´s claim

Step-by-step explanation:

We will test the breeder´s claim at 95% ( CI) or significance level

α = 5 %   α = 0,05    α /2 = 0,025

Sample Information:

sample size   n  = 45

sample mean   x  = 72,5 pounds

Sample standard deviation  s = 16,1

1.-Hypothesis Test:

Null Hypothesis                              H₀        x  =  70

Alternative Hypothesis                  Hₐ        x  ≠  70

Alternative hypothesis contains the information about what kind of test has  to be developed ( in this case it will be a two-tail tets)

2.-z (c) is from z-table     z(c) = 1,96

3.- z(s)  =  ( x - 70 ) / 16,1 / √45

z(s)  =  (72,5 -70 ) *√45 / 16,1

z(s)  = 2,5 * 6,71 / 16,1

z(s)  = 1,04

4.-Comparing  z(s) and z(c)

z(s)  <  z(c)

Then z(s) is in the acceptance region we accept H₀. We don´t have enough evidence to support the breeder´s claim

7 0
3 years ago
Read 2 more answers
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