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Whitepunk [10]
4 years ago
9

What is the greatest common factor of the terms of the polynomial 12x^4 - 6x^3 + 9x^2​

Mathematics
1 answer:
choli [55]4 years ago
3 0

Answer:

3x^{2} is the greatest common factor of the polynomial.

Step-by-step explanation:

Given:

The polynomial is 12x^{4} - 6x^{3} + 9x^{2}

In order to determine the greatest common factor of all the terms, we find the greatest common factor of the coefficients separately and greatest common factor of the variables separately.

So, factors of 12 = 1, 2, <u>3</u>, 4, 6, 12

Factors of 6 = 1, 2, <u>3</u>, 6

Factors of 9 = 1, <u>3</u>, 9

Therefore, the greatest common factor among 12, 6, and 9 is 3.

Now, factors of x^{4} = 1, x, x^{2}, x^{3}, x^{4}

Factors of x^{3} = 1, x, x^{2}, x^{3}

Factors of x^{2} = 1, x, x^{2}

Therefore, the greatest common factor among x^{4}, x^{3},x^{2} is x^{2}.

Hence, the greatest common factor of all the terms of the polynomial is 3x^{2}

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a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti
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The school net ball team drew 2 matches. The team won \frac{5}{8} of total matches played

<h3><u>Solution:</u></h3>

Given, A school netball team won ten matches, lost four and drew \frac{1}{8} of the total played

Let the total number of matches played be "n"

Number of matches drawn = \frac{1}{8} of n

<em>Total matches played = number of won matches + number of lost matches + number of drawn matches</em>

\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}

Taking "n" as common from left hand side,

\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}

So, they played 16 matches in total

Number of matches drawn = \frac{1}{8} of n = \frac{1}{8} \times 16 = 2\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}

\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }

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