Over the last decade, the overall energy consumption of cloud data centers worldwide has remained relatively the same because the technology supporting cloud data centers has become much more energy efficient.
<h3>Why has the energy consumption of cloud data centers remained the same?</h3>
The reason is that servers are said to be six times as heavy as data in terms of energy consumption is one that is seen to be due to improved hardware efficiency.
In regards to cloud, the machines are said to be running by giving web services and other machines room to consumes some level or amount of energy that can be used for working.
Hence, Over the last decade, the overall energy consumption of cloud data centers worldwide has remained relatively the same because the technology supporting cloud data centers has become much more energy efficient.
Learn more about cloud data centers from
brainly.com/question/13440433
#SPJ1
See full question below
Over the last decade, the overall energy consumption of cloud data centers worldwide has remained relatively the same. Why is this so? The technology supporting cloud data centers has become much more energy efficient. There is significantly less customer demand for cloud computing than a decade ago. Cloud providers have placed limits on the amount of data stored at each center. Cloud data centers operate with less computing power than they did in the past.
Answer:
Using three or more vanishing points within a work to create the illusion of space on a two-dimensional surface.
Explanation:
Answer:
To do this you'll need to use malloc to assign memory to the pointers used. You'll also need to use free to unassign that memory at the end of the program using the free. Both of these are in stdlib.h.
#include <stdlib.h>
#include <stdio.h>
#define SIZE_X 3
#define SIZE_Y 4
int main(void){
int **matrix, i, j;
// allocate the memory
matrix = (int**)malloc(SIZE_X * sizeof(int*));
for(i = 0; i < SIZE_X; i++){
matrix[i] = (int *)malloc(SIZE_Y * sizeof(int));
}
// assign the values
for(i = 0; i < SIZE_X; i++){
for(j = 0; j < SIZE_Y; j++){
matrix[i][j] = SIZE_Y * i + j + 1;
}
}
// print it out
for(i = 0; i < SIZE_X; i++){
for(j = 0; j < SIZE_X; j++){
printf("%d, %d: %d\n", i, j, matrix[i][j]);
}
}
// free the memory
for(i = 0; i < SIZE_X; i++){
free(matrix[i]);
}
free(matrix);
return 0;
}
Answer: Transmission rate
Explanation:
Transmission rate is measured in bits per second and it transmitted the data at the different rate across the circuit. The speed in which the data rate is transferred from one device to anther is known as transmission rate.
The transmission rate are always less as compared to signalling rate because the signalling rate contain the total data which basically include the overhead to control the information.
Therefore, transmission rate is the correct option.
A <span>stagflation is my answer.</span>
