Answer:
65 square units
Step-by-step explanation:
Assuming point O refers to the origin, the segment OA has slope ...
m = Δy/Δx = 5/1 = 5
Then the slope of the perpendicular line AP will be the negative reciprocal of this, -1/5.
The x-intercept of the line through (1, 5) with slope -1/5 can be found by setting y=0 in the point-slope equation for that line:
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
0 -5 = (-1/5)(x -1)
25 = x -1 . . . . . . . multiply by -5
x = 26 . . . . . . . add 1
This means ΔOAP has a base length (OP) of 26 units and an altitude of 5 units. Its area is given by the formula ...
A = 1/2bh
A = 1/2(26)(5) = 65 . . . . square units
Triangle OAP has an area of 65 square units.
Answer:
Twelve divide by six times two.
4
Step-by-step explanation:
To solve this problem, first you have to use the order of operations stands for parenthesis, exponents, multiply, divide, add, and subtract from left to right.
First, multiply & divide numbers from left to right.



Therefore, the correct answer is twelve divide by six times two or 4.
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Answer:
Step-by-step explanation:
It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get





Now, From ΔABC and ΔHBC, we have
∠ABC=∠BHC(each90)
∠ACB=∠HCB (Common)
By AA similarity, ΔABC is similar to ΔHBC.
Thus, using the similarity condition, we get



100 ÷44=0.44
0.44×25=11 is the answer
Two divided into five (2/5) would be the answer.
The reason why, is because 2/5 is just another way of saying your going to divide 2 into 5
hope thats what you were looking for.