Answer:
12.8 g
Explanation:
Step 1: Write the balanced neutralization reaction
Al(OH)₃ + 3 HCl ⇒ AlCl₃ + 3 H₂O
Step 2: Calculate the moles corresponding to 17.9 g of HCl
The molar mass of HCl is 36.46 g/mol.
17.9 g × 1 mol/36.46 g = 0.491 mol
Step 3: Calculate the moles of Al(OH)₃ that completely react with 0.491 moles of HCl
The molar ratio of Al(OH)₃ to HCl is 1:3. The reacting moles of Al(OH)₃ are 1/3 × 0.491 mol = 0.164 mol
Step 4: Calculate the mass corresponding to 0.164 moles of Al(OH)₃
The molar mass of Al(OH)₃ is 78.00 g/mol.
0.164 mol × 78.00 g/mol = 12.8 g
Answer:
Double Replacement
Explanation:
Let's consider the following balanced reaction that occurs between aluminum sulfate and tripotassium phosphate.
Al₂(SO₄)₃ + 2 K₃PO₄ ⇒ 2 AlPO₄ + 3 K₂SO₄
This is a double replacement reaction because both salts exchange their cations and anions. So, PO₄³⁻ takes the place of SO₄²⁻ in Al₂(SO₄)₃ and SO₄²⁻ takes the place of PO₄³⁻ in K₃PO₄.
ANSWER
Option A
EXPLANATION
Arrhenius defines an acid as a substance that will produce hydrogen ions as the only positive ion when dissolved in water.
He also defines a base as a substance that contains a hydroxide ion (OH^-).
Hence, the Arrhenius Model of acids and bases applies that is applied to the aqueous solution.
The correct answer is option A
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