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STALIN [3.7K]
3 years ago
10

Objects can be charged when electrons move from one object to another by direct contact 1.Charging by conduction (contact) 2.Cha

rging by conduction (contact), , 3.Charging by friction 4.Static electricity charging by induction
Chemistry
2 answers:
kolezko [41]3 years ago
5 0

Answer:

the one above is correct

Explanation:

-no need-

stellarik [79]3 years ago
4 0

Answer:

Charging by conduction (contact)

Static electricity charging by induction

Explanation:

A body can be charged when another body is made to touch it such that charges are transferred from a charged body to an uncharged body. This is known as charging by contact.

A body can also be charged by induction. In this case, a charged body is only brought near an uncharged body without really touching the uncharged body. Charges are transferred without physical contact of the bodies.

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its the second one alright

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Basic molecules contain more ...
notsponge [240]

Answer:

Option C. hydroxide ions (OH-).

Explanation:

A base is a substance which dissolves in water to produce hydroxide ion (OH-) as the only negative ion. It therefore means that a base contains more hydroxide ions (OH-).

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3 years ago
A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti
MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_3H_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL

Putting values in above equation, we get:

2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M

Thus the molarity of the malonic acid solution is 0.08335 M

5 0
3 years ago
A lead ball is added to a graduated cylinder containing 50.6 ml of water, causing the level of the water to increase to 93.0 mL.
Kamila [148]

42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

<h3>What is a graduated cylinder?</h3>

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

93.0 mL= V_(lead ball) +50.6 ml

V_(lead ball) = 93.0 mL - 50.6 ml

V_(lead ball) = 42.4 ml

Hence, 42.4 ml is the volume in milliliters of the lead ball.

Learn more about the graduated cylinder  here:

brainly.com/question/13386106

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2 years ago
What happens if a cell is unable to get rid of its waste?
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A. The cell will not be able to maintain a stable internal environment. 

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