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Aleks04 [339]
4 years ago
11

Simplify this expression.

Mathematics
1 answer:
Sunny_sXe [5.5K]4 years ago
3 0

58.25n+30p-2

Step-by-step explanation:

Given the expression as;

1 + 4.25n + 32p – 3 + (–2p) + 54n

collect like terms

1-3+4.25n+54n+32p-2p

-2+58.25n+30p

58.25n+30p-2

Learn more

Algebra: brainly.com/question/1280754

Keywords: simplify, expression

#LearnwithBrainly

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Me voy a comprar una barra de cortinas. Como vivo en un doceavo piso, me interesa saber cuál es la longitud máxima que puedo met
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Answer:

The maximum length of the bar I could fit in the elevator is 2.87 meters.

Step-by-step explanation:

<u><em>The question in English is</em></u>

I'm going to buy a curtain rod. Since I live on a twelfth floor, I'm interested in knowing the maximum length I can put in the elevator.

So I take out my pocket tape measure, which only measures up to a meter and I measure the floor which turns out to be a square of 1m x 1m, but for the height it doesn't give.

However, there's a sticker on the lift box that says it has a capacity of 2,500 litres.

With all this information, what is the maximum length of bar that would fit me in the elevator?

step 1

Find the height of the elevator

we know that

The elevator has a capacity of 2,500 litres.

1\ m^3=1,000\ L

so

2,500\ L=2.5\ m^3

The volume of the elevator is given by

V=Bh

where

B is the area of the base

h is the height of the elevator

we have

B=(1)(1)=1\ m^2\\V=2.5\ m^3

substitute

2.5=(1)h\\h=2.5\ m

step 2

Find the diagonal of the base of the elevator

Let

d ---> diagonal of the base of the elevator

Applying the Pythagorean Theorem

d^2=b^2+b^2

substitute

d^2=1^2+1^2

d=\sqrt{2}\ m

step 3

Find the diagonal of the rectangular prism (elevator)

Let

D ----> diagonal of the rectangular prism

d ---> diagonal of the base of elevator

h ----> height of the elevator

Applying the Pythagorean Theorem

D^2=d^2+h^2

substitute

D^2=(\sqrt{2})^2+2.5^2

D^2=8.25\\D=2.87\ cm

therefore

The maximum length of the bar I could fit in the elevator is 2.87 meters.

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