Answer:
A Tape Library
Explanation:
A tape library, sometimes called a tape silo, tape robot or tape jukebox, is a storage device that contains one or more tape drives, a number of slots to hold tape cartridges, a barcode reader to identify tape cartridges and an automated method for loading tapes. It Enables faster data migrations, reduce the complexity of and increase the frequency of backups, and streamline governance in a secure and cost-effective way.
Answer:
Explanation:
The following code is written in Python it doesn't use any loops, instead it uses a recursive function in order to continue asking the user for the inputs and count the number of positive values. If anything other than a number is passed it automatically ends the program.
def countPos(number=input("Enter number: "), counter=0):
try:
number = int(number)
if number > 0:
counter += 1
newNumber = input("Enter number: ")
return countPos(newNumber, counter)
else:
newNumber = input("Enter number: ")
return countPos(newNumber, counter)
except:
print(counter)
print("Program Finished")
countPos()
I will try to give you the best answer I can possibly come up with.
The easy way to get it is to store it into an array of strings and print the array of string backwards. You can do that by starting at the last part of the array down to the first letter.
The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.
int recursiveOddSum(int n) {
if(2n-1==1) return 1;
return (2n-1) + recursiveOddSum(n-1);
}
To prove the correctness of this algorithm by induction, we start from the base case as usual:

by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).
Now we can assume that
returns indeed the sum of the first n-1 odd numbers, and we have to proof that
returns the sum of the first n odd numbers. By the recursive logic, we have

and by induction,
is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So,
is the sum of the first n odd numbers, as required:

We use Boolean Logic operators because it saves more time when searching a topic. This connects pieces of information in a search allowing you to find exactly what you are looking for.