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Ivenika [448]
3 years ago
10

Mary feels confident managing Google Search campaigns and is interested in extending her marketing reach with the help of Google

Display ads. She’s trying to decide whether to create a Standard Display campaign or a Smart Display campaign. Why would Mary choose Standard Display campaigns over Smart Display campaigns?
Computers and Technology
1 answer:
LekaFEV [45]3 years ago
7 0

Answer:

She wants full control over all aspects of her Display campaigns is correct.

Explanation:

With the help of Google Display ads, she feels comfortable in running Search campaigns and seems to be engaged in expanding its marketing scope. She is difficult to determine whether it will build a regular show campaign or a campaign for smart displays. And she opts for full control of all facets of her Show campaigns.

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X = 0
cricket20 [7]

The missing line would be x+= num

This means that every time a number is selected from the range it is added to the value of x.

3 0
3 years ago
The ____ method returns an integer that represents the location of the substring within the string.
enot [183]

Insert Method

it is used to returns an integer that speaks to the area of the substring inside the string.

5 0
3 years ago
Identify the following as True or False.
Leni [432]

Answer:

The answer to this question as follows:

1) False

2) False

3) True

Explanation:

The description of the above option as follows

  • In option 1, A single character variable must be contained in one quote mark, but it is based on the alphabet, which is a specific device, and the price of a continued character varies from one device to another, that's why it is false.
  • In option 2, This option is wrong because in assembly language the identifier value must not exceed the length than 247 characters.
  • In option 3, It is correct because in the variable declaration the first char should be a letter, _, @ or $letter. A total of 1-247 characters. The default case is insensitive.

5 0
3 years ago
Nadia's productivity at work is being hurt due to the large quantity of unwanted e-mail she receives. What steps can she take to
anastassius [24]

Answer:

Hi,

The best option in the list is <u>stop posting her e-mail address on newsgroups.</u>

Explanation:

Unwanted e-mail is categorized as a spam email.These emails can not be entirely avoided because we use the Internet thus it is recommended that you filter them.A program called my email client can help to filter spam though in some cases, it might not be effective.

The techniques Nadia can employ in this case is to hidden her email address when visiting newsgroups.News groups are forums online where people discuss certain topic.Avoid publishing the email in these web sites can hide her tackle this problem. Additionally, Nadia could train the filter serach feature in her email box through repoting such emails using the report button present, avoid responding/openning spam  or use a third party program to track spam emails and block them.

Wish you Luck!

8 0
3 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
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