Given:
m∠B = 44°
Let's find the following measures:
m∠A, m∠BCD, m∠CDE
We have:
• m∠A:
Angle A and Angle B are interior angles on same side of a transversal.
The interior angles are supplementary.
Supplementary angles sum up to 180 degrees
Therefore, we have:
m∠A + m∠B = 180
m∠A + 44 = 180
Subtract 44 from both sides:
m∠A + 44 - 44 = 180 - 44
m∠A = 136°
• m,∠,BCD:
m∠BCD = m∠A
Thus, we have:
m∠BCD = 136°
• m∠CDE:
Angle C and angle CDE form a linear pair.
Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.
Thus, we have:
m∠D = m∠B
m∠D = 44°
m∠CDE + m∠D = 180
m∠CDE + 44 = 180
Subract 44 from both sides:
m∠CDE + 44 - 44 = 180 - 44
m∠CDE = 136°
ANSWER:
• m∠A = 136°
,
•
,
• m∠BCD = 136°
,
•
,
• m∠CDE = 136°
Answer:
The answer is 14.
Step-by-step explanation:
Since all of the angles of a triangle add up to be 180, then all you have to do is add the 2 angles together that you have and subtract that number from 180. For example 141+25=166, so, 180-166=14. 14 would be the measure of the third angle.
Answer: Its a cone
Explanation:
When a right angle triangle is rotated about any of its leg a cone is formed.
So, if the page is 12 inches wide, that's the width of the page, 12, minus the width of the photo, 7 1/2. 12 - 7 1/2 = 4 1/2.
Now, we need to divide 4 1/2 by 2, so it will be even on both sides.
4 1/2 divided by 2 = 2 1/4.
He should put the picture 2 1/4 inches from each side of the page.
