Find the equation of the line with slope = -7 and passing through (-7,51). write your equation in the form y=mx+b

Mathematics

1 answer:

muminat3 years ago

4 0

Answer:

y = -7x + 2

Step-by-step explanation:

Since we do not have the y-intercept (or, when the x is 0) We will use the Slope Form Formula (y - y1 = m(x - x1)) to find the Slope Intercept Form Formula (y = mx + b)

Point: (-7,51)

Slope: -7

y - y1 = m(x - x1)

y - 51 = -7(x - (-7))

y - 51 = -7(x + 7)

y - 51 = -7x - 49

y = -7x - 49 + 51

y = -7x + 2

You might be interested in

What is 1.61 rounding to the nearest tenth

kkurt [141]

6 is in the 5entha place. 1 is smaller than 5 so u bring it down so it would be 1.6

5 0

3 years ago

45) Toby cut one of these shapes out of a piece of paper folded

Vlad1618 [11]

Answer:

B) the bell because it is symmetrical down the middle

4 0

3 years ago

Read 2 more answers

A baseball is thrown into the air with an upward velocity of 30 ft/s. its initial height was 6 ft, and its maximum height is 20.

marissa [1.9K]

Check the picture below.

where is the -16t² coming from? that's Earth's gravity pull in feet.

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{30}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{6}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-16t^2+30t+6 \\\\[-0.35em] ~\dotfill$

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+30}t\stackrel{\stackrel{c}{\downarrow }}{+6} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)$

$\bf \left(-\cfrac{30}{2(-16)}~~,~~6-\cfrac{30^2}{4(-16)} \right)\implies \left( \cfrac{30}{32}~,~6+\cfrac{225}{16} \right)\implies \left(\cfrac{15}{16}~,~\cfrac{321}{16} \right) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{\stackrel{\textit{how many}}{\textit{seconds it took}}}{0.9375}~~,~~\stackrel{\stackrel{\textit{how many feet}}{\textit{up it went}}}{20.0625})~\hfill$