Answer:
Step-by-step explanation:
<h3>A.</h3>
The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>
The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
Answer: I believe those would be opposite angles (aka vertically opposite angles).
Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Work:
6/15 = x/1
To get from 15 to 1, you have to divide by 15. So, to make an equal field, divide 6 by 15.
6 : 15 is the same as 2 : 5 or 0.4.
30/80 = x/1
To get from 80 to 1, you have to divide by 80. So, to make an equal field, divide 30 by 80.
30 : 80 is the same as 3 : 8 or .875.
Comparing the two, 30 : 80 is greater than 6 : 15.
Hope this helps. Have a good day.
Answer:
It is vertically stretched by a factor of 200 and shifted 10 units up.
Step-by-step explanation:
cool like that
