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Lostsunrise [7]
3 years ago
11

Find the greatest two consecutive odd intergers whose sum is less than 85

Mathematics
1 answer:
mel-nik [20]3 years ago
8 0
5x7=35 7x9=63 9x11=99. 99 is too high so it has to be 7 and 9.
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How do you find slope
alisha [4.7K]

Step-by-step explanation:

Hi there!

To find slope you use the change of y over change of x formula. You first need to ordered pairs to plug into the equation.

Formula:

(Y1-Y2)/(X1-X2)

7 0
3 years ago
Read 2 more answers
If you start with a number, add 5 , then multiply by 7, the result is133. what was the original number?
Natalija [7]
(x+5)*7=133
7x+35=133
7x=98
x=98/7
x=14
5 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
Which is the value of g(-5) if g(x) = 3.40 – 8
Mila [183]

Answer:

Step-by-step explanation:

If you have written g(x) correctly then g(-5) = 3.40 - 8 = -4.6

If you meant to write g(x) = 3.40x - 8, then g(-5) = -25

4 0
3 years ago
Work out the volume of the shape​
pashok25 [27]

Answer:

\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

V_c=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3

The formula of a volume of a sphere:

V_s=\dfrac{4}{3}\pi R^3

R - radius

Therefore the formula of a volume of a half-sphere:

V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3

We have R = 7cm. Substitute:

V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3

The volume of the given shape:

V=V_c+V_{hs}

Substitute:

V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3

7 0
3 years ago
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