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Crazy boy [7]
3 years ago
8

Who knows this? I need help ASAP

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

A=674.5cm square

Step-by-step explanation:

First, using pythagoras theorem:

Cos x =2/5-90=66.4

This is angle ACD.

Then 1/2 absinC=1/2(5x4)sin66.4

=664.2cm square

Next, find angle DCB by 90-23.578=66.4

And angle CBD by 180-30-66.4=23.578

Use sin23.578=4.58/H

H=11.45cm(length of d)

Now, use 1/2absinC again to find the area of another part of the triangle.

1/2 11.45x4.5sin23.6=10.31cm square

Lastly add them up!

A=664.2-10.31cm =674.5cm square.

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Y intercept is the value of y when x is equaled 0.

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Slope intercept form is

y = mx + b

In this equation, b is the y intercept.

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Which of the following could be represented by -8?
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Option A: drop of 8 meters would be correct because a drop in this case indicates something has been removed. -8 equals 8 below 0.

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3 years ago
Please help for 10 points and help with both questions please.
DedPeter [7]
Question 21 
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Discount price = 80 - 80x10/100

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3 years ago
A rectangular storage container with an open top is to have a volume of 10m3. Thelength of its base is twice the width. Material
frutty [35]

Answer:

$163.54

Step-by-step explanation:

Volume of rectangular container = 10m^3

Length = 2(width)

Material for the base cost $10 per square meter

Material for the side cost $6 per square meter

Volume = L*B*H

L= 2W

V = (2W).W. H

10 = 2W^2.H

H = 10 /2W^2

H = 5/W^2

Let C(w) = cost function

C(w) = 10(L.W) + 6(2.L.H + 2.W.H)

= 10(2W.W) + 6(2.2W.H + 2.W.H)

= 10(2W^2) + 6(4W.H + 2.W.H)

= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)

= 20W^2 + 6(20/W + 10/W)

= 20W^2 + 6((10+20)/W)

= 20W^2 + 6(30/W)

C(w) = 20W^2 + 180/W

To find the minimum value, differentiate C with respect to w

C'(w) = 40W - 180/W^2

Put C'(w) = 0

0 = 40W - 180/W^2

40W = 180/W^2

40W^3 = 180

W^3 = 180/40

W^3 = 4.5

W = cube rt(4.5)

W = 1.65m

C = 20(1.65)^2 + 180/1.65

C = 54.45 + 109.09

C= $163.54

Minimum cost = $163.54

6 0
3 years ago
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