x = ±
i
rearrange the equation and equate to zero
2x² - 6x = - 5 ⇒ 2x² - 6x + 5 = 0
this doesn't factor with integers, hence use the quadratic formula to solve
with a = 2, b = - 6 and c = 5
x = (6 ± √(36 - 40 ) )/4
= (6 ± √(-4) ) / 4
= (6 ± 2i ) / 4
x = ±
i
The solution to the system of equation are x = -2 and y = 3
<h3>How to find the solution of a system of equation?</h3>x + 3y = 7
2x + 4y = 8
Let's isolate x in the first equation
x = 7 - 3y
substitute the value of x in the second equation.
Therefore,
2(7 - 3y) + 4y = 8
14 - 6y + 4y = 8
-2y = 8 - 14
-2y = -6
y = -6 / -2
y = 3
Hence,
x + 3(3) = 7
x = 7 - 9
x = -2
learn more on equation here: brainly.com/question/12926248
#SPJ1
