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2 years ago

Use the foil method to find the product below. (x+3) (x^2-6x)

Mathematics

1 answer:

Scorpion4ik [409]2 years ago

5 0

x^3 - 3x^2 - 18x

Using the FOIL method, I arrived at my solution!

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If the area of the triangle is 10 cm squared, what is the missing height?

just olya [345]

Answer:

4cm

Step-by-step explanation:

A= 1/2 bxh

10=1/2x5xh

10= 2.5h

4= h

hope this helps!

8 0

3 years ago

Read 2 more answers

Help Needed -Thanks

Gelneren [198K]

Answer:

− 2 √ 3

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

5 0

2 years ago

Find the value of x.

Marina86 [1]

X=10 because you use Pythagorean’s theorem!

8 0

2 years ago

Read 2 more answers

Which value for slope represents the steepest line? explain -12/5 -3 -2/3 or -1

pogonyaev

The greater the absolute value of the slope, the steeper the line.

Therefore, slope of -3 represents the steepest line.

7 0

3 years ago

The line 3x-8y=k cuts the x-axis and y- axis at the point A and B respectively. If the area of ∆AOB =12sq.units, find the value

Sladkaya [172]

Given:

The equation is:

$3x-8y=k$

It cuts the x-axis and y- axis at the point A and B respectively.

The area of ∆AOB =12 sq.units.

To find:

The value of k.

Solution:

We have,

$3x-8y=k$

Substituting $x=0$ to find the y-intercept.

$3(0)-8y=k$

$0-8y=k$

$y=\dfrac{k}{-8}$

$y=-\dfrac{k}{8}$

Substituting $y=0$ to find the x-intercept.

$3x-8(0)=k$

$3x-0=k$

$x=\dfrac{k}{3}$

Area of a triangle is:

$A=\dfrac{1}{2}\times base\times height$

The height of the ∆AOB is $OB=\dfrac{k}{8}$ because distance cannot be negative and the base of the ∆AOB is $OA=\dfrac{k}{3}$ . So, the area of the ∆AOB is:

$A=\dfrac{1}{2}\times \dfrac{k}{8}\times \dfrac{k}{3}$

$A=\dfrac{k^2}{48}$

It is given that, the area of ∆AOB = 12 sq.units.

$\dfrac{k^2}{48}=12$

$k^2=576$

$k=\pm \sqrt{576}$

$k=\pm 24$

Therefore, the value of k is either 24 or -24.

4 0

3 years ago