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maxonik [38]
3 years ago
6

the unit digitsof a two numberis 1 less than twice the ten digit. if the sum of tje digits is 9, find the number.

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0
Are you sure this is written correctly? Any number whose digits add to 9 is divisible by 9.  For a 2 digit number then, your choices are
18, 27, 36, 45, 54, 63, 72, and 81.  None of these has the property that for the 2 digit number AB that B=2A-1.  Solving your question algebraically is possible but you get fractional digits.
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The course for a boat race starts at point A and proceeds in the direction of S52'E for 1 hour at 8 knots to point B and then in
KATRIN_1 [288]

Answer:

20.823 nautical miles

S20°E

Step-by-step explanation:

I assume you mean ° (degrees), not ' (minutes).  There are 60 minutes in 1 degree.

S52°E means "south, 52° east", or 52° east of south.

S50°W means "south, 50° west", or 50° west of south.

1 knots = 1 nautical mile / hour, so the boat first travels 8 nautical miles from A to B, then 4.5 nautical miles from B to C, then finally back to A.

If we say A is at the origin, then the coordinates of B are:

(8 sin 52°, -8 cos 52°)

And the coordinates of C are:

(8 sin 52° − 4.5 sin 50°, -8 cos 52° − 4.5 cos 50°)

(2.857, -7.818)

So the distance from A to C is:

x = √(2.857² + (-7.818)²)

x ≈ 8.323

And the total distance of the race is:

d = 8 + 4.5 + 8.323

d = 20.823

The compass bearing from A to C is:

θ = atan(2.857 / 7.818)

θ ≈ S20°E

8 0
3 years ago
PLEASE ANSWER ASAP!! WILL GIVE 50 POINTS! AND BRAINLIST!
levacccp [35]

\frac{3}{5}  -  \frac{1}{4}  =  \frac{7}{20}
then
\frac{7}{20}  \div  \frac{7}{10}  =  \frac{1}{2}
4 0
3 years ago
When it comes to maps its hard for me:) please help!
Umnica [9.8K]
Your answers will be A,B,D,
5 0
3 years ago
Can someone solve this with steps cause idk how to solve the radicals
IceJOKER [234]
\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9


to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.
8 0
3 years ago
A cup is 6.4 cm tall, not including a 0.6 cm lip. Cups are stacked inside one another. You may want to draw a diagram to help yo
Tasya [4]
If you think about how it works when cups are stacked. you will begin with the height of the cup plus the height of the lip you would then add just the heigt of the lips until you get to the height needed. so your answer should be 19 cups
0 0
3 years ago
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