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svetlana [45]
3 years ago
14

. Simplify: 2(n + 5).

Mathematics
2 answers:
nordsb [41]3 years ago
8 0

Answer:2n +10

Step-by-step explanation:

2*n= 2n

2*5= 10

Colt1911 [192]3 years ago
4 0

Answer:

2n+10

Step-by-step explanation:

2(n + 5)

Multiply by 2

2(n)+2(5)

Open the bracket

2Xn + 2X5

2n+10

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A bag contains 31 checkers—13 red and 18 black. Determine whether the events "a red checker is selected, not replaced and then a
Ipatiy [6.2K]

Answer:

dependent, 39/155

Step-by-step explanation:

Since the checkers are not replaced, the events are dependent since the number of checkers in the bag  when you pick the second time depends on the first pick.

31 checkers—13 red and 18 black.

P(red) = red/ total

          = 13/31

Keep the checker

Then 30 checkers—12 red and 18 black.

P(black) = black/ total

          = 18/30 = 3/5

P ( red, keep,black) = 13/31 *3/5

                                   39/155

8 0
3 years ago
Seven less than three times a number is 5. Find the number
Anit [1.1K]

Step-by-step explanation:

it is 12 because 12 - 7 is 5 the number 4 is the number multiplied by 3

7 0
2 years ago
Read 2 more answers
In 2017 the population of Rexburg, Idaho was 28,337 people. The population was expected to grow at a rate of about 1.26% per yea
frez [133]

Answer:

30,122

Step-by-step explanation:

This probably isn't the fastest way to solve but....

28,337x1.26%= 357

357x5=1785

28,337+1785=30,122

The 5 came from the # of years the population is increasing

6 0
3 years ago
In accordance with 14 CFR Part 107, at what maximum altitude can you operate an sUAS when inspecting a tower with a top at 1,000
Svetllana [295]

Answer:

The max altitude you can operate an sUAS on these given conditions is 1400ft AGL.

Step-by-step explanation:

6 0
3 years ago
the height of an object thrown vertically is given by s=-16t^2+100t+200. Height is meter and time is n seconds.
koban [17]

Answer:

456.25m

Step-by-step explanation:

Since the question did not ask for what to find, we can as well look for the maximum height reached by the object

Given the height of an object thrown vertically expressed as;

s=-16t^2+100t+200.

At max height,

dS/dt = 0

-32t+100 = 0

-32t = -100

t = 100/32

t = 3.125s

Get the Max height

s(3.125) = -16(3.125)²+100(3.125)+200

s(3.125) = -156.25+312.5+200

s(3.125) = 456.25m

Hence the maximum height reached by the object is 456.25m

5 0
3 years ago
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