Divide the numerator by the denominator to find out
I would also agree with no solutions
Answer:
<h2>b. 40 yd²</h2>
Step-by-step explanation:
We have the square and the right triangle.
The formula of an area of a square:
![A_{\boxed{}}=a^2](https://tex.z-dn.net/?f=A_%7B%5Cboxed%7B%7D%7D%3Da%5E2)
a - length of side
The formula of an area of a right triangle:
![A_\triangle=\dfrac{ab}{2}](https://tex.z-dn.net/?f=A_%5Ctriangle%3D%5Cdfrac%7Bab%7D%7B2%7D)
a,b - legs
We have:
SQUARE:
a = 4 yd
![A_{\boxed{}}=4^2=16\ yd^2](https://tex.z-dn.net/?f=A_%7B%5Cboxed%7B%7D%7D%3D4%5E2%3D16%5C%20yd%5E2)
RIGHT TRIANGLE:
a = 6 yd, b = 4 yd + 4 yd = 8 yd
![A_\triangle=\dfrac{(6)(8)}{2}=(3)(8)=24\ yd^2](https://tex.z-dn.net/?f=A_%5Ctriangle%3D%5Cdfrac%7B%286%29%288%29%7D%7B2%7D%3D%283%29%288%29%3D24%5C%20yd%5E2)
The area of the figure:
![A=A_{\boxed{}}+A_\triangle\\\\A=16\ yd^2+24\ yd^2=40\ yd^2](https://tex.z-dn.net/?f=A%3DA_%7B%5Cboxed%7B%7D%7D%2BA_%5Ctriangle%5C%5C%5C%5CA%3D16%5C%20yd%5E2%2B24%5C%20yd%5E2%3D40%5C%20yd%5E2)
Answer:
135
Step-by-step explanation:
9 x 15 = 135
Answer: At noon the temperature outside of Hector's home was 4 degree warmer than the temperature outside of gale's home.
Step-by-step explanation:
Here, x represents the number of hours after noon while g(x) and f(x) represents the temperature of gale's and hector's home respectively in x hours.
Since, at noon, x = 0
And, by the table g(x=0) = -1
That is, the temperature of gale's home is -1° F at noon.
And, by the given graph, f(x=0) = 3
That is, the the temperature of hector's home is 3° F at noon.
And, f(0)-g(0) = 3-(-1) = 4°F
That is, the difference between the temperature of hector's home at noon and the temperature of gale's home at noon is 4°F.