Prove that: 27^10-9^14 is divisible by 24

2 answers:

6 0

$27^{10}-9^{14}=3^{30}-3^{28}=3^{28}(3^2-1)=3^{28}\cdot 8=3^{27}\cdot3\cdot8=3^{27}\cdot24$

4 0

27^10-9^14

=3^30 - 3^28

=3^28 (3^2-1)

=3^28 ·8

=2^27 ·3·8

=3^27 · 24 is divisible by 24

You might be interested in

Alik [6]

Answer:

There are none.

Step-by-step explanation:

<u>No calculus involved:</u>

The line, in slope-intercept form, has equation $y=-10x+17$ , ie is always decreasing (easy to spot applying the definition)

Meanwhile, $y=e^{5x}$ is always increasing over its domain.

At no point the tangent will be decreasing.

<u>Let's use calculus</u>

We are to solve the equation $y'(x) = -10 \rightarrow 5e^{5x} = -10 \rightarrow e^{5x}=-2$ which has no real solutions.

8 0

3 years ago

siniylev [52]

Answer:

<h2>The correct answer for this question is 78.</h2>

Step-by-step explanation:

The average or mean of any variable or mathematical phenomenon is calculated as the division of the sum of all the numbers or items within the particular variable by the total number of items or numbers within the variable.
In this case, the marks of the 4 exams in the semester are 77,90,85 and 100 respectively.There are total 5 exams in the semester.
Let's suppose that the marks for the 5th exam is x.
Therefore, based on the mathematical formula to compute average or mean,to get an overall average of 86 including all the 5 exams, one has to get:-

$\frac{77+90+85+100+x}{5}=86$