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egoroff_w [7]
2 years ago
15

Prove that: 27^10-9^14 is divisible by 24

Mathematics
2 answers:
lutik1710 [3]2 years ago
6 0

27^{10}-9^{14}=3^{30}-3^{28}=3^{28}(3^2-1)=3^{28}\cdot 8=3^{27}\cdot3\cdot8=3^{27}\cdot24

Alexandra [31]2 years ago
4 0

27^10-9^14

=3^30 - 3^28

=3^28 (3^2-1)

=3^28 ·8

=2^27 ·3·8

=3^27 · 24 is divisible by 24

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Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

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Area of the shaded portion in ΔBCD = 52.36 - 43.3

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                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

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