Question

Prove that: 27^10-9^14 is divisible by 24

Answer 1

$27^{10}-9^{14}=3^{30}-3^{28}=3^{28}(3^2-1)=3^{28}\cdot 8=3^{27}\cdot3\cdot8=3^{27}\cdot24$

Answer 2

27^10-9^14

=3^30 - 3^28

=3^28 (3^2-1)

=3^28 ·8

=2^27 ·3·8

=3^27 · 24 is divisible by 24