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2 years ago

Please anyone I’m desperate

Mathematics

2 answers:

poizon [28]2 years ago

7 0

Step-by-step explanation:

calm down ! just breathe.

these are totally simple additions and one also very simple subtraction to make.

you know that you can combine terms based on the same variable, right ?

3a + 9a = 12a

7b - b = 6b

the result is then

12a + 6b, so B is the right answer.

this bases already on the same principle of actual numbers.

2×3 + 5×3 = 7×3 because this is also

(2 + 5) × 3

6×5 + 6×3 = 6×8 because this is also

6 × (5 + 3)

7×8 - 4×8 = 3×8 because this is also

(7 - 4) × 8

and so on.

Savatey [412]2 years ago

3 0

Answer:

the answer is B) 12a+6b

Step-by-step explanation:

3+9=12 so 3a+9a=12a,

7-1=6 so 7b-(1)b=6b

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Answer:

Step-by-step explanation:

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3 years ago

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Please help me <br> 3(x + 2) * 10 * 7 divided by 70 - 2 (x+2)<br><br> Simplify

I am Lyosha [343]

Answer:

= 105(x+2)/33-x

Step-by-step explanation:

Given the expression

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= 3(x+2)*70÷70 - 2(x+2)

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2 years ago

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Answer:

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<C = <D

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Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

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