Answer:
The height of the prism is equal to 
Step-by-step explanation:
we know that
The volume of a rectangular prism is equal to

where
B is the area of the base of the prism
h is the height of the prism
In this problem we have


substitute in the formula and solve for h


Answer:
Decompose the figure into two rectangles and add the areas.
Step-by-step explanation:
We can draw a vertical line segment from the smaller section of the rectangle straight down. This would cut the rectangle into 2 smaller rectangles. We can then find the area of each rectangle and add them to find the area of the composite figure.
Answer:A on edge
Step-by-step explanation:
Answer:

Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)