Answer:
(4x the answer ) can you help with my question
Step-by-step explanation:
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at </span></span> A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36
Explanation:
If 
then taking the reciprocal gives
Answer:
Step-by-step explanation:
Answer:
x = 4 sqrt(2)
Step-by-step explanation:
This is a right triangle so we can use trig functions
sin theta = opp/ hypotenuse
sin 45 = 4/x
Multiply x to each side
x sin 45 = 4/x *x
x sin 45 = 4
Divide each side by sin 45
x sin 45 / sin 45 = 4 /sin 45
x = 4/ sin 45
We know sin 45 = sqrt(2)/2
x = 4/ sqrt(2) /2
x = 8/ sqrt(2)
We do not leave a sqrt in the denominator so multiply by sqrt(2)/ sqrt(2)
x = 8/ sqrt(2) * sqrt(2)/sqrt(2)
x = 8 * sqrt(2) /2
x = 4 sqrt(2)
