p=36
because 15 is 3 times 5 so just multiply the perimeter
Answer:
first u should make your equation: y= -1/5 (x-5) - 3
y= -1/5x +1 -3
y= -1/5 x -2
then u should setting some number like 1 ,2 ..... instead of *x* and when u done this u should dissolve it (now your *y* is came out too) so you have your x,y now
According to the points you get, you put it on the chart and connect it
if you do not understand something, tell me to draw on paper so you can understand better
Answer:
not statistically significant at ∝ = 0.05
Step-by-step explanation:
Sample size( n ) = 61
Average for student leader graduates to finish degree ( x') = 4.97 years
std = 1.23
Average for student body = 4.56 years
<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>
H0( null hypothesis ) : u = 4.56
Ha : u ≠ 4.56
using test statistic
test statistic ; t = ( x' - u ) / std√ n
= ( 4.97 - 4.56 ) / 1.23 √ 61
= 2.60
let ∝ = 0.05 , critical value = -2.60 + 2.60
Hence we wont fail to accept H0
This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05
Is this for a quiz? It looks familiar
