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Gennadij [26K]
3 years ago
5

4. Assume that you have a part-time job at which you work 20 hours per week at the rate

Mathematics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

0.125

7.50/60=1.25

since there 60 minutes in one hour you would divide the hourly rate by 60.

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The angle of elevation of the top of a tower from a point 100m away is 45 degrees. What is the height of the tower to the neares
OLEGan [10]
<h3>Answer: 100 meters</h3>

===========================================

Explanation:

If you draw out the diagram, then you'll find that a 45-45-90 triangle forms. The nice thing about this type of triangle is that the two legs are always the same length. The horizontal leg is 100 meters, so the vertical leg must also be 100 meters.

Side note: this type of triangle is an isosceles right triangle.

---------

You could use the tangent rule to get the same thing

tan(angle) = opposite/adjacent

tan(45) = 100/x

1 = 100/x

1*x = 100

x = 100

In this case, the opposite leg is the vertical leg since it is furthest from the angle of elevation.

5 0
3 years ago
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6. Find the value of y.<br> 5<br> 16
Svetllana [295]
3.59999
or 3.6
hopefully this helps you!
4 0
2 years ago
If a(x) = 3x + 1 and b(x)= squareroot x-4, what is the domain of (b*a)(x)?
oksano4ka [1.4K]

\boxed{ \ x \geq 1 \ } or can be written as \boxed{ \ [1, \infty) \ }

<h3>Further explanation</h3>

This is a question about the composition of functions and how to get a domain function.

Given \boxed{ \ a(x) = 3x + 1 \ } and \boxed{ \ b(x) = \sqrt{x - 4} \ }.

We will form (b o a)(x) and then determine the domain.

<u>Step-1</u>

\boxed{ \ (b \circ a)(x) = b(a(x)) \ }

Replace each appearance of x in b(x) with \boxed{ \ a(x) = 3x + 1 \ }.

\boxed{ \ (b \circ a)(x) = \sqrt{(3x + 1) - 4} \ }

Thus, \boxed{ \ (b \circ a)(x) = \sqrt{3x - 3} \ }

<u>Step-2</u>

To be defined, the value under the radical sign must not be negative. Therefore, the domain of (b \circ a)(x) = \sqrt{3x - 3} are processed as follows.

\boxed{ \ 3x - 3 \geq 0 \ }

Both sides added by 3.

\boxed{ \ 3x \geq 3 \ }

Both sides divided by 3.

\boxed{ \ x\geq 1 \ }

Thus, the domain of (b \circ a)(x) = \sqrt{3x - 3} is \boxed{ \ x \geq 1 \ } or can be written as \boxed{ \ [1, \infty) \ }

<h3>Learn more</h3>
  1. If f(x) = x² – 2x and g(x) = 6x + 4, for which value of x does (f o g)(x) = 0? brainly.com/question/1774827
  2. Solve for the value of the function composition brainly.com/question/2142762
  3. Look for rotation rules in the transformation brainly.com/question/2992432

Keywords: composition of function, if a(x) = 3x + 1, and, b(x) = √(x-4), what is the domain of, (b o a)(x), b(a(x)), defined, the value, under the radical sign, must not be negative,

4 0
3 years ago
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Three friends go grocery shopping together and each buys same kind of oranges. Lamar buys 2 pounds and pays 7.00 Enrico buys 3 p
xenn [34]

Answer: B

Step-by-step explanation:

8 0
3 years ago
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The formula equals 16t squared is used to approximate the distance​ s, in​ feet, that an object falls freely from rest in t seco
Brut [27]
The equation is actually h(t)=-16t^2+1437.  Free fall is always -16t^2 as the position function.  We are looking for how long it takes the object to hit the ground.  In other words, the height of an object is 0 when it is laying on the ground, so how long (t) did it take to get there? We will then set that position equal to 0 and solve for t.  0=-16t^2+1437.  If we subtract 1437 from both sides and divide by -16, we have t^2=89.8125.  Taking the square root of both sides gives us, rounded to the nearest tenth, t = 9.5 or t=-9.5.  The 2 things in math that will never EVER be negative are time and distance/length, so -9.5 is out.  That means that it took just about 9.5 seconds for the object to fall to the ground from a height of 1437 feet when pulled on by the force of gravity.
6 0
3 years ago
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