$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}$

$\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}$

5 0

2 years ago

What is the solution to this system of linear equations?<br><br> x + y = 4<br><br> x − y = 6

Amiraneli [1.4K]

X+y = 4, therefore y = 4-x when you rearrange the equation.
You can subsitute this in: x-(4-x) = 6
-4+x = 6-x
x=10-x
2x = 10
x = 5
Substitute x into the previous equation:
5+y = 4
y = 4-5
y = -1

5 0

3 years ago

Read 2 more answers

What's is the answer to 15n-19n

Art [367]

Answer:

-4n

Step-by-step explanation:

8 0

2 years ago

Question 5 plz help !!!!!!!

deff fn [24]