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elena55 [62]
3 years ago
15

Kevin, who has liability limits of $20,000/$40,000/$20,000 and a $500 collision deductible, is involved in an accident. Due to h

is negligence he runs into a Rolls Royce. Three people sustained bodily injuries in the Rolls Royce. The driver's injuries were worth $1,000,000, a passenger received injuries worth $12,500, and another passenger received injuries of $7,100. How much will the PAP pay for these bodily injuries?
Business
1 answer:
harina [27]3 years ago
4 0

Answer:

Amount to pay by PAP = $39,600

Explanation:

The liability limits of $20,000/$40,000/$20,000 implies that the highest amount PAP will pay for driver's injuries is $20,000, while the highest to pay for the first of two passenger is $40,000 and $20,000 for second passenger.

Since the a passenger received injuries worth $12,500, and another passenger received injuries of $7,100, the PAP will the actual amount and $20,000 for the driver's injuries. The total can therefore be calculated as follows:

Amount to pay by PAP = $20,000 + $12,500 + $7,100 = $39,600

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Answer:

See explanation section

Explanation:

(a) December 1     Cash             Debit    $18,000

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(b) December 31   Unearned revenue     Debit    $3,600

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<em>Note: As the company started performing, after the completion of 1st month, i.e., December 1 to December 31, the advance money started expiring because of providing services. Moreover, as the service is performed evenly for 5 months, the 1st month's revenue = $(18,000/5) = $3,600.</em>

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3 years ago
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Answer:

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The correct answer is letter A.

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