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elena55 [62]
3 years ago
15

Kevin, who has liability limits of $20,000/$40,000/$20,000 and a $500 collision deductible, is involved in an accident. Due to h

is negligence he runs into a Rolls Royce. Three people sustained bodily injuries in the Rolls Royce. The driver's injuries were worth $1,000,000, a passenger received injuries worth $12,500, and another passenger received injuries of $7,100. How much will the PAP pay for these bodily injuries?
Business
1 answer:
harina [27]3 years ago
4 0

Answer:

Amount to pay by PAP = $39,600

Explanation:

The liability limits of $20,000/$40,000/$20,000 implies that the highest amount PAP will pay for driver's injuries is $20,000, while the highest to pay for the first of two passenger is $40,000 and $20,000 for second passenger.

Since the a passenger received injuries worth $12,500, and another passenger received injuries of $7,100, the PAP will the actual amount and $20,000 for the driver's injuries. The total can therefore be calculated as follows:

Amount to pay by PAP = $20,000 + $12,500 + $7,100 = $39,600

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