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love history [14]
3 years ago
10

On 49 the wording is confsuing me can someone help please it is greatly appreacated

Mathematics
1 answer:
Lilit [14]3 years ago
5 0
Basically find a recipe for guacamole and times the amount of guacamole it can make by 2 1/4.
Good Luck!
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Solve the system by substitution.<br> x = 9y<br> x-5y=20
storchak [24]

Step-by-step explanation:

hope this helps you! have a great day

4 0
3 years ago
Look at photo for the question and answer choices... NO LINKS OR BLANK ANSWERS
Firdavs [7]

Answer:

Rhombus Square

Step-by-step explanation:

7 0
3 years ago
Given that r=(9,8,3),v=(6,7,-1)and w=(-3,3,7), evaluate (r+v) w
lakkis [162]

Answer:

(-45,45,14)

Step-by-step explanation:

(r+v)*w=((9,8,3)+(6,7,-1))*(-3,3,7)=(15,15,2)*(-3,3,7)=(-45,45,14)

Does this help (I'm not sure of the rightness of this answer), if it did, please mark brainliest

4 0
3 years ago
Jason volunteered at the pet shelter twice as many times as keith. Noah volunteered three times more often than jason. Keith vol
Alchen [17]

Answer:

y = 6\cdot z

y - Number of times that Noah volunteered at pet shelter.

z - Number of times that Keith volunteered at pet shelter.

Step-by-step explanation:

After reading the statement of the problem, the following variables are described below:

x - Number of times that Jason volunteered at pet shelter.

y - Number of times that Noah volunteered at pet shelter.

z - Number of times that Keith volunteered at pet shelter.

The following two relations are presented herein:

Noah and Jason

y = 3\cdot x

Jason and Keith

x = 2\cdot z

The relationship between the number of times Noah and Keith volunteered is:

y = 6\cdot z

7 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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