if the diameter of a circle is 15, its radius is half that or 7.5.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7.5%20%5Cend%7Bcases%7D%20A%3D%5Cpi%20%287.5%29%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7BA%3D176.625%7D%20)
Answer:
About 28.27.
Step-by-step explanation:
To figure out the area of the base, you just use the formula to find the area of a circle. Which is;
A = r^2 * pi
(r stands for radius)
Answer:
(2)(18)x
=36x
Step-by-step explanation:
sorry if its wrong i need points and i didnt quit know what this was but sorry if this was wrong and sorry if i didnt help
Answer:
352x^2
Step-by-step explanation:
40\times 1.25x\times 2.20x\times 3.2040×1.25x×2.20x×3.20
(40)1.25x2.20x3.20
+ − . ln > <
× ÷ / log ≥ ≤
( ) logx = %
1 Take out the constants.
(40\times 1.25\times 2.20\times 3.20)xx(40×1.25×2.20×3.20)xx
2 Simplify 40\times 1.2540×1.25 to 5050.
(50\times 2.20\times 3.20)xx(50×2.20×3.20)xx
3 Simplify 50\times 2.2050×2.20 to 110110.
(110\times 3.20)xx(110×3.20)xx
4 Simplify 110\times 3.20110×3.20 to 352352.
352xx352xx
5 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
352{x}^{2}352x
2
Done
