The smallest 3 common multiples of 2 and 3 are 6, 12, and 18 .
The smallest 3 common multiples of 3 and 6 are also 6, 12, and 18 .
Answer:
2 7/20
Step-by-step explanation:
here u go boo
Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
Step-by-step explanation:
x-intercept: Set y = 0 and solve for x:
0 = mx + b, or mx = -b, or x = -b/m. x-intercept is then (-b/m, 0)
y-intercept: Set x = 0 and solve for y: y = m(0) + b, or y = b. y-intercept is then
(0, b).
