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3 years ago

I really need help with this: [image linked below]

Mathematics

1 answer:

klio [65]3 years ago

6 0

1 & 5 are corresponding because they are in the same place on the lines.
1 & 8 are alternate exterior because they are on opposite sides of the transversal and they are on the outside of the parallel lines.
2 & 6 are corresponding.
2 & 7 are alternate exterior.
3 & 5 are alternate interior because they are on opposite sides of the transversal, and they are in between the parallel lines.
3 & 6 are consecutive interior angles because they are on the same side interior of the parallel lines.
3 & 8 are corresponding.
4 & 5 are consecutive interior.
4 & 6 are alternate interior.
4 & 7 are corresponding.

Hope this helps you now and in the future =)

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Select the correct answer

Paladinen [302]

Answer:

a) We get $\mathbf{A+B=x^2-2x+1}$

So, Is the result of A+B is a polynomial:Yes

b) We get $\mathbf{A-B=6x^3-7x^2+2x-1}$

So, Is the result of A-B is a polynomial:Yes

c) We get $\mathbf{A.B=9x^6+21x^5-18x^4+9x^3-3x^2}$

So, Is the result of A.B is a polynomial:Yes

Step-by-step explanation:

We are giving the polynomial equations:

$A= 3x^2(x-1)\\B=-3x^3+4x^2-2x+1$

We need to find

a) A+B

$A+B=3x^2(x-1)+(-3x^3+4x^2-2x+1)\\A+B=3x^3-3x^2-3x^3+4x^2-2x+1\\A+B=3x^3-3x^3-3x^2+4x^2-2x+1\\A+B=x^2-2x+1\\$

So, we get $\mathbf{A+B=x^2-2x+1}$

So, Is the result of A+B is a polynomial:Yes

b) A-B

$A-B=3x^2(x-1)-(-3x^3+4x^2-2x+1)\\A-B=3x^3-3x^2+3x^3-4x^2+2x-1\\A-B=3x^3+3x^3-3x^2-4x^2+2x-1\\A-B=6x^3-7x^2+2x-1\\$

So, we get $\mathbf{A-B=6x^3-7x^2+2x-1}$

So, Is the result of A-B is a polynomial:Yes

c) A . B

$A.B=3x^3(-3x^3+4x^2-2x+1)-3x^2(-3x^3+4x^2-2x+1)\\A.B=9x^6+12x^5-6x^4+3x^3+9x^5-12x^4+6x^3-3x^2\\A.B=9x^6+12x^5+9x^5-6x^4-12x^4+3x^3+6x^3-3x^2\\A.B=9x^6+21x^5-18x^4+9x^3-3x^2$

So, we get $\mathbf{A.B=9x^6+21x^5-18x^4+9x^3-3x^2}$

So, Is the result of A.B is a polynomial:Yes

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2 years ago

Rectangle PQRS will be transformed to the points P^ prime (2,0) , Q^ prime (7,0),R^ prime (7,-2) , and S^ prime (2,-2)What type

Svet_ta [14]

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navik [9.2K]

Answer:

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3 years ago

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Find the area of quadrilateral with vertices at points (3,0)(4,5)(-1,4)(-2,-1)

guapka [62]

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Step-by-step explanation:

Let 's complete our quadrilateral to a rectangle ; and subtract from it the area highlighted in red

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