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ale4655 [162]
3 years ago
13

What is the number of roots for polynomial function of f(x) = (x^2 + 6)^2

Mathematics
1 answer:
Lena [83]3 years ago
5 0

Answer:

x=±√6i

Step-by-step explanation:

(x^{2} +6)^{2} =0

x^{2}+6=0

x^{2} =-6

x=±√6i

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