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Allisa [31]
3 years ago
14

One of the three economic questions deals with deciding

Mathematics
2 answers:
Oxana [17]3 years ago
7 0

Answer:

The correct answer is A: what goods and services should be produced.

Step-by-step explanation:

drek231 [11]3 years ago
3 0
One of the three economic questions deals with deciding what goods and services must be produced from available resources.

Here are the Three Main Economic Questions
1) Who consumes the goods and services produced in society?
2) What goods and services must be produced in society?
3) How should goods and services be produced in society?

<span>These questions are very important because it deals on how available resources are allocated to produce essential goods and services demanded by consumer
</span>
You might be interested in
what is the volume of a cylinder in cubic cm with a height of 9cm and a base diameter of 16cm round to the nearest tenths place
salantis [7]
So 9 x 16 =?? So u have to times those and u should get the answer
3 0
2 years ago
Pablo wants to get a grade of at least 95 in math this semesterSo far he has test scores of 89 98, 97 and 92. He will take his l
Alex Ar [27]

Answer:

the answer is 97 if you're rounding but 99 if you want exactly 95

Step-by-step explanation:

if you add all the previous grades up it'll add up to 376 and then when you add 97 and then divide it by 5 (the total amount of assignments) it'll add up to 94.6 which rounds up to a 95 unless you want it a 95 exactly which would probably be 99

3 0
3 years ago
Read 2 more answers
One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe
sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                                 P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of people who disagree with the statement = \frac{1812}{2625} = 0.69

           n = sample of respondents = 2625

           p = population proportion of people who disagree with statement

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

<u>So, 99% confidence interval for the population proportion, p is ;</u>

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5% level

                                                   of significance are -2.58 & 2.58}  

P(-2.58 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.58) = 0.99

P( -2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [ \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

= [ 0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } , 0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } ]

 = [0.667 , 0.713]

Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

5 0
3 years ago
A (5-x) = bx - 8<br> x =
inysia [295]
Your awnser is : x= 8+5a/a+b
4 0
3 years ago
List the integers that satisfy both these inequalities, 2x+9 -12
Flura [38]

Answer:

x < -10.5

Step-by-step explanation:

list the integers that satisfy both these inequalities, 2x+9 <-12

Subtract 9 from  both sides;

2x +9 - 9 < -12-9

2x < -21

x < -21/2

x < -10.5

<em>Hence all the integers are values of x less than 10.5</em>

<em></em>

4 0
3 years ago
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