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marissa [1.9K]
3 years ago
11

HELP PLEASE} I have the question on the image.

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0
9+13+9+10+10+9+10+10+11+9=100
100/10=10
Hope That Helped
choli [55]3 years ago
4 0
The answer is 10 Years
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Peter the Leprechaun has 526 gold bars that he arranges evenly into 24 pots. Each gold bar weighs 2.2 pounds. A) How many bars o
zimovet [89]

Answer: 21

Step-by-step explanation: The amount the gold bar weighs is extra information and is meant to throw you off, 526/24 is 21.9 but because you can’t have a decimal amount of gold bars it’s just 21 in each pot.

6 0
3 years ago
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Which number is larger? (1 mark)<br><br> 0.67 or<br> 2/3
KengaRu [80]

Answer:

0.67

Step-by-step explanation:

2/3= to 0.66 which means 0.67 would be technally larger than 0.66

8 0
2 years ago
Write a quadratic function in standard form with a leading coefficient of 1 for the given set of zeros. 7 and 4
Viefleur [7K]

We are given : Zeros x=7 and x=4 and leading coefficent 1.

In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.


6 0
3 years ago
Janet has read 17 of the 20 books she borrowed from the library. What percentage of the books she borrowed has she read?
Advocard [28]
17 times 5 so 85 percent.......
8 0
3 years ago
Du/dr=(1+sqrt(r))/(1+sqrt(u))_
Maslowich
Solution is supposed to be as follows
<span>u+<span>2 / 3</span><span> u<span>^3/2</span></span>
=r+<span>2 / 3</span><span> r^<span>3/2</span></span> + <span>c</span></span>
4 0
3 years ago
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