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Mumz [18]
2 years ago
14

Can some one tell me where they go? Please and thank you!!

Mathematics
2 answers:
Alchen [17]2 years ago
8 0
Answers:

A. 4 inches = pencil
B. 6 feet = tablecloth
C. 1 meter = person’s leg
D. 5 yards = ladder
E. 6 centimeters = insect
F. 2 millimeters = grain of rice
G. 3 kilometers = foot race

hope this is right :)
can you give brainliest plz
avanturin [10]2 years ago
5 0

Answer:

The same as the top also thanks for the points and did you get a warning for your last post

Step-by-step explanation:

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Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. I came up with the answer 25
alexira [117]

Step-by-step explanation:

To check if a solution is extraneous, simply plug it back into the original equation.  If it works, then solution isn't extraneous.

√(2x−1) = 7

√(2(25)−1) = 7

√(50−1) = 7

√(49) = 7

7 = 7

So the solution isn't extraneous.

3 0
3 years ago
What kinds of information are creditors looking for?
ValentinkaMS [17]
Well, since a creditor is defined as "<span>a person or company to whom money is owe", that probably means they are looking for financial information, or maybe your address to keep up with you and assuring you pay back the owed money. I could be wrong though</span>
4 0
3 years ago
What’s the answer?????
S_A_V [24]
30 units^3 (just count the blocks inside) :)
3 0
3 years ago
How to determine if the columns of a matrix are linearly independent?
astra-53 [7]
Let's consider an arbitrary 2x2 matrix as an example,

\mathbf A=\begin{bmatrix}\mathbf x&\mathbf y\end{bmatrix}=\begin{bmatrix}x_1&y_1\\x_2&y_2\end{bmatrix}

The columns of \mathbf A are linearly independent if and only if the column vectors \mathbf x,\mathbf y are linearly independent.

This is the case if the only way we can make a linear combination of \mathbf x,\mathbf y reduce to the zero vector is to multiply the vectors by 0; that is,

c_1\mathbf x+c_2\mathbf y=\mathbf 0

only by letting c_1=c_2=0.

A more concrete example: suppose

\mathbf A=\begin{bmatrix}1&2\\4&8\end{bmatrix}

Here, \mathbf x=\begin{bmatrix}1\\4\end{bmatrix} and \amthbf y=\begin{bmatrix}2\\8\end{bmatrix}. Notice that we can get the zero vector by taking c_1=-2 and c_2=1:

-2\begin{bmatrix}1\\4\end{bmatrix}+\begin{bmatrix}2\\8\end{bmatrix}=\begin{bmatrix}-2+2\\-8+8\end{bmatrix}=\mathbf 0

so the columns of \mathbf A are not linearly independent, or linearly dependent.
8 0
3 years ago
Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime
Aleks [24]

Answer:

Its A

Step-by-step explanation:

i just took the quiz and got it right

8 0
3 years ago
Read 2 more answers
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