Answer:
<em>The sample size 'n' = 721</em>
<em>Number of cars 'n' = 721</em>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
<em>Given Population proportion 'p' = 0.40</em>
<em>Given Margin of error = 0.03</em>
<em>90% of level of significance </em>
<em> </em>
<em></em>
<em>The Margin of error is determined by</em>
<em></em>
<em></em>
![0.03 = \frac{1.645 X \sqrt{0.40(1-0.40) } }{\sqrt{n} }](https://tex.z-dn.net/?f=0.03%20%3D%20%5Cfrac%7B1.645%20X%20%5Csqrt%7B0.40%281-0.40%29%20%7D%20%7D%7B%5Csqrt%7Bn%7D%20%7D)
on calculation , we get
0.03√n = 0.8058
![\sqrt{n} = \frac{0.8058}{0.03} = 26.86](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B0.8058%7D%7B0.03%7D%20%3D%2026.86)
squaring on both sides , we get
n = 721.45≅721
<u><em>conclusion</em></u>:-
<em>The sample size 'n' = 721</em>
<em>Number of cars 'n' = 721</em>
Answer: The distributive property.
5(10+4)
=5*10+5*4
=50+20
=70
I would say I guess it is about around 0.198387.
2560-1944= 616gallons
7 days in a week or 14 days in two weeks
616gallons / 14days = 44 gallons / 1 day
Notice in the fraction we have
(Gallons / days)
Now if you filled the take up the entire way
2560 gallons
We have gallons and the question wants the amount of days
Thus to cancel gallons we set the equation up as such
(2560 gallons) x (1 day / 44 gallons) = 58.18 days
Or 58 days