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2 years ago

Which is the equation of the line that contains the points (-1, -5) and (2,1)

Mathematics

2 answers:

QveST [7]2 years ago

8 0

Answer:

y=2x-3

Step-by-step explanation:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

podryga [215]2 years ago

3 0

Answer:

y=2x-3

Step-by-step explanation:

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Write the equation of the line passing through the points (6,2) and (-2,-2). The equation of the line is [] Please helppp!!

AURORKA [14]

Answer:

Step-by-step explanation:

slope=(-2-2)/(-2-6)=-4/-8=1/2

eq. of line is

y-2=1/2(x-6)

2y-4=x-6

2y=x-6+4

2y=x-2

or y=1/2x-1

4 0

2 years ago

What is the length of RS.

Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0

3 years ago

Show how to make one addend the next tens number. complete the new addition sentence. 15+37=?

Dafna1 [17]

52, 15+37=52 llllllllll

7 0

3 years ago

Read 2 more answers

Use the discriminant to determine the number of solutions and types of solutions for the quadratic equation, below. Then answer

Setler79 [48]

Answer:

A. Discriminant = 116

B. Number of solutions for the quadratic equation = 2

C. Type of solutions (circle one):Imaginary

D. Type of solutions (circle one):irrational

Step-by-step explanation:

The given quadratic equation is

${x}^{2} + 8x = 13$

We rewrite in standard form to get;

${x}^{2} + 8x - 13 = 0$

The discriminant is

$D = {b}^{2} - 4ac$

where a=1, b=8, c=-13

We substitute to get:

$D = {8}^{2} - 4 \times 1 \times - 13$

$D = 64 + 52$

$D = 116$

Since the discriminant is great than zero, we have two distinct real roots

6 0

3 years ago

Please help .!!!!!!!!!!!!!!!!!!!

Mrrafil [7]

Answer:

The answer is C

Step-by-step explanation:

8 0

3 years ago