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Natalka [10]
2 years ago
6

According to records in a large hospital, the birth weights of newborns have a symmetric and bell-shaped relative frequency dist

ribution with mean 6.8 pounds and standard deviation 0.5 Approximately what proportion of babies are born with birth weight under 6.3 pounds?
Mathematics
1 answer:
Kamila [148]2 years ago
8 0

Answer:

15.9% of babies are born with birth weight under 6.3 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.8 pounds

Standard Deviation, σ = 0.5

We are given that the distribution of  birth weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(birth weight under 6.3 pounds)

P(x < 6.3)

P( x < 6.3) = P( z < \displaystyle\frac{6.3 - 6.8}{0.5}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < -1) = 0.159 = 15.9\%

15.9% of babies are born with birth weight under 6.3 pounds.

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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

           (a)/(a^2-16)+(2/(a-4))-(2/(a+4))=0 

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<span> 3.1 </span>     Factoring: <span> a2 - 16</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
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</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check : 16 is the square of 4
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Factorization is :       (a + 4)  •  (a - 4) 

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<span> 4.1 </span>   Find the Least Common Multiple 

      The left denominator is :      <span> (a+4) •</span> (a-4) 

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<span><span>                  Number of times each Algebraic Factor
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Add the two equivalent fractions which now have a common denominator

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One solution was found :

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