sin θ = csc θ = cos θ = sec θ = tan θ = cot θ = Let θ be an acute angle of a right triangle. ... Homework 4 – Radians & Degrees; Co-terminal; Standard Position.
Answer:a=3.6 and b=4.8
Step-by-step explanation:(a^2)+(b^2)=(c^2)
Where c is hypotenuse is equal to 6. A right triangle is also known as a 3,4,5 triangle where the 2 legs are 3 and 4 and hypotenuse is 5. Find the factor in size difference by dividing your hypotenuse of 6 by the hypotenuse of 5 you get 1.2. Now multiply the 3 and 4 by 1 2 to get your answers of 3.6 and 4.8.
To check work simply plug in your legs as a and b
(3.6^2)+(4.8^2)=(6^2)
(12.96)+(23.04)=(36)
first we need to find the hypotenuse by using a^2 + b^2 = c^2 (where c is the hypotenuse and a and b are the other sides)
8^2 + 5^2 = 64 + 25 = 89, so c = sqrt89.
cosine is adjacent over hypotenuse: 8/sqrt89
rationalize the fraction: (8*sqrt89)/89
the answer is C.
Hi there! :)
Answer:
(a) ≈ 3.61 cm.
(b) = 2.77 cm².
Use the Pythagorean theorem to solve for the side-length of DC. Let "s" represent the side-lengths:
s² + s² = 26
2s² = 26
Divide both sides by 2 to simplify:
s² = 13
Take the square root of both sides:
s = √13 ≈ 3.61 cm.
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Calculate the shaded region by subtracting the area of the arc from the area of the square. DC represents the radius of the circle that the arc is apart of. Therefore:
Area of arc AC = 1/4 (πr²)
Solve for the area:
AC = 1/4 (π · (3.61)²)
AC = 1/4 (40.92)
AC = 10.23 cm²
Subtract this area from the area of the square (A = s²)
A = (√13)²
A = 13 cm²
13 - 10.23 = 2.77 cm²
Therefore, the solutions are:
(a) ≈ 3.61 cm.
(b) = 2.77 cm².
Answer:
It's 8
Step-by-step explanation: