3 years ago

GEOMETRY. PLEASE HELP

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

7 0

Answer:

Here, Diameter of the whole tube = 10 m

Diameter of the inner tube= 10mm - 2 mm= 8mm

Now,

Area of the shaded region =1/4 ×πd^2

=1/4×3.14×8^2

=50.24 mm^2

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if my grade is 69% what will my grade be if i got a 3.3 of 4 on a essay and it's worth 25% of my grade?

juin [17]

Answer:

72.4%

Step-by-step explanation:

The essay is 25% of your grade, and the rest is 75% of your grade.

25 (3.3/4) + 75 (0.69) ≈ 72.4

6 0

3 years ago

Can anyone answer this pls!!!!!!!!!!

gizmo_the_mogwai [7]

u₁₂ represents the amount of loan remaining after 12 years

<h3>How to interpret u₁₂?</h3>

The function is given as:

u₀ = 8000

$u_n = u_{n-1}(1 + 0.054) - 500$

Given that the subscript n in $u_n$ represents number of years and $u_n$ represents the amount left to be paid after n years.

We can conclude that:

u₁₂ represents the amount of loan remaining after 12 years

Read more about loan at
brainly.com/question/26011426

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2 years ago

Officer Brimberry wrote 16 tickets for traffic violations last week, but only 2 tickets this week. What is the percent decrease?

Verdich [7]

Answer:

87.5%

Step-by-step explanation:

It decreased by 16 - 2 or 14, and since he wrote 16 tickets last week, the answer is 14/16 in percent form, or 7/8 = 87.5%.

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3 years ago

Are lines GH and G'H' perpendicular? Why or why not? Yes, they intersect at one point. Yes, their slopes are negative reciprocal

Solnce55 [7]

Answer:

Step-by-step explanation:

B yes their slopes are negative reciprocals

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3 years ago

Help please!<br> 6x^2+2x-9=0<br> A 6.4, -8.4<br> B 1.1, -1.4<br> C -2.2, 2.8<br> D -1.1, -1.4

Yakvenalex [24]

$6x^2+2x-9=0\\\\a=6;\ b=2;\ c=-9\\\\\Delta=b^2-4ac\to\Delta=2^2-4\cdot6\cdot(-9)=220\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-2-\sqrt{220}}{2\cdot6}=\dfrac{-2-\sqrt{220}}{12}\approx-1.4\\\\x_2=\dfrac{-2+\sqrt{220}}{2\cdot6}=\dfrac{-2+\sqrt{220}}{12}\approx1.1$

Answer: B. 1.1; -1.4.

6 0

3 years ago

GEOMETRY. PLEASE HELP ​

GEOMETRY. PLEASE HELP