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3 years ago

b) What is the sum of the exterior angles of the equilateral triangle ∠M + ∠R + ∠X? Explain your reasoning. (2 points)

Mathematics

1 answer:

kykrilka [37]3 years ago

3 0

120 degrees is anwser because 180-60 is 120 you know the angles of triangle are 60 because it is an equateral triangle

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The length of ZX is 2 units. What is the perimeter of triangle XYZ? 5 + + 2 units 5 + 3 units 5 + + 2 units 10 + 2 units

Shtirlitz [24]

Answer:

B) 5 + 3√5 units

Step-by-step explanation:

The length of ZX is 2√5 units. What is the perimeter of triangle XYZ?

A) 5 +√3 + 2 √5 units

B) 5 + 3√5 units

C) 5 + √6 + 2√5 units

D) 10 + 2√5 units

From the diagram attached, point X is at (-1, 4), Y(3, 1), Z(1, 0).

The distance between two point

$O(x_1,y_1)\ and\ A(x_2,y_2)\ is\ given\ as:\\\\OA=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

The lengths of the sides of the triangle are:

$|XY| = \sqrt{(3-(-1))^2+(1-4)^2}=\sqrt{25} =5\ unit\\ \\|XZ|= \sqrt{(1-(-1))^2+(0-4)^2}=\sqrt{20} =2\sqrt{5} \ unit\\\\|YZ|= \sqrt{(1-3)^2+(0-1)^2}=\sqrt{5} \ unit$

The perimeter of the triangle is the sum of all the sides, i.e.

Perimeter = |XY| + |YZ| + |XZ| = 5 + 2√5 + √5 = 5 + 3√5

7 0

3 years ago

the u.s.s harry truman is an aircraft carrier that is 1,092 feet long. find the length in ft and in please help

kodGreya [7K]

The U.S.S Harry Truman is 1,092 feet (333 m) long, 257 feet (78 m) wide and is as high as a twenty-four-story building, at 244 feet (74 m)

3 0

3 years ago

Anna gets $10 dollars everyday but on sunday on sunday she gets $17 dollars she wants to buy a dress that is 2,000 dollars if sh

Allisa [31]

No, 10x5=50
50x6=300
17x6= 102
102+300=402

4 0

3 years ago

70% of the students applying to a university are accepted. Assume the requirements for a binomial experiment are satisfied for 1

marshall27 [118]

Answer:

a) 0.3826

b) 0.9894

Step-by-step explanation:

We are given the following information:

We treat students accepted at university as a success.

P(students accepted at university) = 70% = 0.70

Then the number of students accepted at university follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

a) P( 8 or more will be accepted)

$P(x \geq 8) = P(x = 8) + P(x = 9) + P(X=10)\\\\= \binom{10}{8}(0.7)^8(1-0.7)^2 + \binom{10}{9}(0.7)^9(1-0.7)^1+ \binom{10}{10}(0.7)^{10}(1-0.7)^0\\\\= 0.2334 + 0.1210 + 0.0282\\= 0.3826$

b) P(4 or more will be accepted)

$P(x \geq 4) =1 - P(x = 0) - P(x = 1) - P(X=2)-P(x=3)\\\\=1 - ( \binom{10}{0}(0.7)^0(1-0.7)^{10} + \binom{10}{1}(0.7)^1(1-0.7)^9+ \binom{10}{2}(0.7)^{2}(1-0.7)^8+ \binom{10}{3}(0.7)^{3}(1-0.7)^7 )\\\\= 1 - 0.0106\\= 0.9894$