Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
To answer this question, you first need to know what SohCahToa is.
S- opposite over hypotenuse
C- adjacent over hypotenuse
T- opposite over adjacent
In this situation, they have made it easier for you as they have given you the quotient of the opposite and adjacent sides (3.4) . Now in order to find an angle, you take the inverse of your expression. So instead of just Tan, you would plug in Tan^-1. So plug it in:
Tan^-1 (3.4)
Answer is 73.6 degrees.
The second one would be 4 inches.
Answer:
41
Step-by-step explanation:
an = a1 + (n-1)d
a_n = the nᵗʰ term in the sequence = 10
a_1 = the first term in the sequence = 5
d = the common difference between terms = 4
a10 = 5 + (10-1)4
a10 = 5 + (9)4
a10 = 5 + 36
a10 = 41
Csc is the inverse of sin. This means the formula in regards to a triangle for csc is h/o, unlike o/h for sin. csc can also be knows as 1/sin.
