Question

A chemist pours 1 mol of zinc granules into one beaker and 1 mol of zinc chloride powder into another beaker. What do the two samples have in common?

Answer 1

Answer is:  two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.

Answer 2

Answer:

Beaker-1 has same number of zinc atoms as that of the zinc ions in beaker-2.

Explanation:

In beaker-1 , we have added 1 mol of zinc granules.

1 mol = $6.022\times 10^{23}$ atoms

In beaker-1 $6.022\times 10^{23}$ atoms of zinc are present.

In beaker-2, we have added 1 mole of zinc chloride.

$ZnCl_2(aq)\rightarrow Zn^{2+}(aq)+2Cl^-(aq)$

1 mole of zinc chloride gives 1 mole of zinc chloride gives one mole of zinc ions and 2 moles of  chloride ions.

1 mol of Zinc ion = $6.022\times 10^{23}$ ions

The both samples have:

$6.022\times 10^{23}$ zinc atoms = $6.022\times 10^{23}$ zinc ions

Beaker-1 has same number of zinc atoms as that of the zinc ions in beaker-2.