Protons, neutrons, and electrons are the fundamental subatomic particles.
You have to use the equation q=mcΔT and solve for T(final).
T(final)=(q/mc)+T(initial)
q=the amount of energy absorbed or released (in this case 868J)
m=the mass of the sample (in this case 15.6g)
c= the specific heat capacity of the substance (in this case 2.41 J/g°C)
T(initial)=the initial temperature of the sample (in this case 21.5°C)
When you plug everything in, you should get 44.6°C.
Therefore the final temperature of ethanol is 44.6°C
I hope this helps. Let me know if anything is unclear.
Answer:
1.33 x 10⁻³ mol/L
Explanation:
The solubility of a gas in a liquid is directly proportional to its partial pressure .This is know as Henry´s law and is given by the formula:
S(g) = Kh x P
where S = solubility of the gas
Kh = henry´s constant for the gas
P = partial pressure of the gas above solution
we are told to assume that the composition of the air in the tank is the same as on land, hence its partial pressure and we know nitrogen composition in air is 78 %, so the partial pressure of N₂ is:
P N₂ = 0.78 x 2.73 atm = 2.13 atm
Now we can calcualte the solubility as follows:
S N₂ = 6.26 x 10⁻⁴ mol / L·atm x 2.13 atm = 1.33 x 10⁻³ mol/ L
They expect the Universe to continue expanding. Right now, the evidence is that the expansion is speeding up. They also expect entropy to continue increasing, so in the distant future, there will not be any free energy left to support life, for example.
Answer:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
